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123720672513901 is a prime number
BaseRepresentation
bin11100001000010111110110…
…101111001000111101101101
3121020001120200101112020000111
4130020113312233020331231
5112204014414130421101
61115044254201300021
735026344412554511
oct3410276657107555
9536046611466014
10123720672513901
113646a708274211
1211a61a8aa94611
135405a6a208b48
14227a1809b4141
15e483d2c61251
hex7085f6bc8f6d

123720672513901 has 2 divisors, whose sum is σ = 123720672513902. Its totient is φ = 123720672513900.

The previous prime is 123720672513863. The next prime is 123720672513913. The reversal of 123720672513901 is 109315276027321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123709783800100 + 10888713801 = 11122490^2 + 104349^2 .

It is a cyclic number.

It is not a de Polignac number, because 123720672513901 - 27 = 123720672513773 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123720672513301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61860336256950 + 61860336256951.

It is an arithmetic number, because the mean of its divisors is an integer number (61860336256951).

Almost surely, 2123720672513901 is an apocalyptic number.

It is an amenable number.

123720672513901 is a deficient number, since it is larger than the sum of its proper divisors (1).

123720672513901 is an equidigital number, since it uses as much as digits as its factorization.

123720672513901 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 952560, while the sum is 49.

The spelling of 123720672513901 in words is "one hundred twenty-three trillion, seven hundred twenty billion, six hundred seventy-two million, five hundred thirteen thousand, nine hundred one".