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12391983013783 is a prime number
BaseRepresentation
bin1011010001010011101110…
…1111101101111110010111
31121212122212121021101011211
42310110323233231332113
53111012240122420113
642204444242242251
72416201614445612
oct264247357557627
947778777241154
1012391983013783
113a4845739785a
121481796056387
136bb73611b3a9
1430babd135179
15167525ab5b3d
hexb453bbedf97

12391983013783 has 2 divisors, whose sum is σ = 12391983013784. Its totient is φ = 12391983013782.

The previous prime is 12391983013693. The next prime is 12391983013793. The reversal of 12391983013783 is 38731038919321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12391983013783 - 29 = 12391983013271 is a prime.

It is a super-2 number, since 2×123919830137832 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12391983013793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6195991506891 + 6195991506892.

It is an arithmetic number, because the mean of its divisors is an integer number (6195991506892).

Almost surely, 212391983013783 is an apocalyptic number.

12391983013783 is a deficient number, since it is larger than the sum of its proper divisors (1).

12391983013783 is an equidigital number, since it uses as much as digits as its factorization.

12391983013783 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5878656, while the sum is 58.

The spelling of 12391983013783 in words is "twelve trillion, three hundred ninety-one billion, nine hundred eighty-three million, thirteen thousand, seven hundred eighty-three".