Base | Representation |
---|---|
bin | 111001101110010001… |
… | …1011101000110100101 |
3 | 102211221221102020122121 |
4 | 1303130203131012211 |
5 | 4012332044203203 |
6 | 132540211225541 |
7 | 11645554140445 |
oct | 1633443350645 |
9 | 384857366577 |
10 | 123959366053 |
11 | 48630915476 |
12 | 200358a82b1 |
13 | b8c657c813 |
14 | 5ddd120125 |
15 | 33578a10bd |
hex | 1cdc8dd1a5 |
123959366053 has 2 divisors, whose sum is σ = 123959366054. Its totient is φ = 123959366052.
The previous prime is 123959366033. The next prime is 123959366057. The reversal of 123959366053 is 350663959321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 122869177729 + 1090188324 = 350527^2 + 33018^2 .
It is a cyclic number.
It is not a de Polignac number, because 123959366053 - 217 = 123959234981 is a prime.
It is a super-4 number, since 4×1239593660534 (a number of 45 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123959366057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61979683026 + 61979683027.
It is an arithmetic number, because the mean of its divisors is an integer number (61979683027).
Almost surely, 2123959366053 is an apocalyptic number.
It is an amenable number.
123959366053 is a deficient number, since it is larger than the sum of its proper divisors (1).
123959366053 is an equidigital number, since it uses as much as digits as its factorization.
123959366053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3936600, while the sum is 52.
The spelling of 123959366053 in words is "one hundred twenty-three billion, nine hundred fifty-nine million, three hundred sixty-six thousand, fifty-three".
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