Search a number
-
+
123994049 is a prime number
BaseRepresentation
bin1110110001111…
…11111111000001
322122022112212012
413120333333001
5223220302144
620145342305
73033634454
oct730777701
9278275765
10123994049
1163a9a623
1235637995
131c8c4b7a
141267949b
15ad43e9e
hex763ffc1

123994049 has 2 divisors, whose sum is σ = 123994050. Its totient is φ = 123994048.

The previous prime is 123994009. The next prime is 123994051. The reversal of 123994049 is 940499321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118113424 + 5880625 = 10868^2 + 2425^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123994049 is a prime.

Together with 123994051, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 123993997 and 123994015.

It is not a weakly prime, because it can be changed into another prime (123994009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61997024 + 61997025.

It is an arithmetic number, because the mean of its divisors is an integer number (61997025).

Almost surely, 2123994049 is an apocalyptic number.

It is an amenable number.

123994049 is a deficient number, since it is larger than the sum of its proper divisors (1).

123994049 is an equidigital number, since it uses as much as digits as its factorization.

123994049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 41.

The square root of 123994049 is about 11135.2615146659. The cubic root of 123994049 is about 498.6551178272.

The spelling of 123994049 in words is "one hundred twenty-three million, nine hundred ninety-four thousand, forty-nine".