1240000411213 has 4 divisors (see below), whose sum is σ = 1240037407840. Its totient is φ = 1239963414588.

The previous prime is 1240000411189. The next prime is 1240000411261. The reversal of 1240000411213 is 3121140000421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1240000411213 is a prime.

It is a super-2 number, since 2×1240000411213² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1240000411613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18447993 + ... + 18515086.

It is an arithmetic number, because the mean of its divisors is an integer number (310009351960).

Almost surely, 2^{1240000411213} is an apocalyptic number.

It is an amenable number.

1240000411213 is a deficient number, since it is larger than the sum of its proper divisors (36996627).

1240000411213 is an equidigital number, since it uses as much as digits as its factorization.

1240000411213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36996626.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1240000411213 its reverse (3121140000421), we get a palindrome (4361140411634).

The spelling of 1240000411213 in words is "one trillion, two hundred forty billion, four hundred eleven thousand, two hundred thirteen".