1240001411433 has 8 divisors (see below), whose sum is σ = 1653341707296. Its totient is φ = 826664361600.

The previous prime is 1240001411431. The next prime is 1240001411443. The reversal of 1240001411433 is 3341141000421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1240001411433 - 2¹ = 1240001411431 is a prime.

It is a super-3 number, since 3×1240001411433³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (1240001411431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 295618 + ... + 1602308.

It is an arithmetic number, because the mean of its divisors is an integer number (206667713412).

Almost surely, 2^{1240001411433} is an apocalyptic number.

It is an amenable number.

1240001411433 is a deficient number, since it is larger than the sum of its proper divisors (413340295863).

1240001411433 is a wasteful number, since it uses less digits than its factorization.

1240001411433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1623015.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1240001411433 its reverse (3341141000421), we get a palindrome (4581142411854).

The spelling of 1240001411433 in words is "one trillion, two hundred forty billion, one million, four hundred eleven thousand, four hundred thirty-three".