Base | Representation |
---|---|
bin | 11100001100011101000011… |
… | …011011001011101101100011 |
3 | 121021001101121002112101220001 |
4 | 130030131003123023231203 |
5 | 112223113304243032042 |
6 | 1115421200021400431 |
7 | 35055533435101141 |
oct | 3414350333135543 |
9 | 537041532471801 |
10 | 124001132002147 |
11 | 36568648348844 |
12 | 11aa8300269117 |
13 | 54263448cc45a |
14 | 228998887c591 |
15 | e50849bb8bb7 |
hex | 70c7436cbb63 |
124001132002147 has 2 divisors, whose sum is σ = 124001132002148. Its totient is φ = 124001132002146.
The previous prime is 124001132002117. The next prime is 124001132002177. The reversal of 124001132002147 is 741200231100421.
It is a balanced prime because it is at equal distance from previous prime (124001132002117) and next prime (124001132002177).
It is an emirp because it is prime and its reverse (741200231100421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 124001132002147 - 235 = 123966772263779 is a prime.
It is not a weakly prime, because it can be changed into another prime (124001132002117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62000566001073 + 62000566001074.
It is an arithmetic number, because the mean of its divisors is an integer number (62000566001074).
Almost surely, 2124001132002147 is an apocalyptic number.
124001132002147 is a deficient number, since it is larger than the sum of its proper divisors (1).
124001132002147 is an equidigital number, since it uses as much as digits as its factorization.
124001132002147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 124001132002147 its reverse (741200231100421), we get a palindrome (865201363102568).
The spelling of 124001132002147 in words is "one hundred twenty-four trillion, one billion, one hundred thirty-two million, two thousand, one hundred forty-seven".
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