Base | Representation |
---|---|
bin | 1011010001110010010110… |
… | …1100111001110000000011 |
3 | 1121220110002110211121021201 |
4 | 2310130211230321300003 |
5 | 3111131103444031202 |
6 | 42212324043402031 |
7 | 2416612410230065 |
oct | 264344554716003 |
9 | 47813073747251 |
10 | 12400203111427 |
11 | 3a5099542488a |
12 | 14832aab23317 |
13 | 6bc4461344b1 |
14 | 30c25cb33735 |
15 | 16785758a387 |
hex | b4725b39c03 |
12400203111427 has 2 divisors, whose sum is σ = 12400203111428. Its totient is φ = 12400203111426.
The previous prime is 12400203111319. The next prime is 12400203111451. The reversal of 12400203111427 is 72411130200421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12400203111427 - 223 = 12400194722819 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12400203111395 and 12400203111404.
It is not a weakly prime, because it can be changed into another prime (12400203111467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200101555713 + 6200101555714.
It is an arithmetic number, because the mean of its divisors is an integer number (6200101555714).
Almost surely, 212400203111427 is an apocalyptic number.
12400203111427 is a deficient number, since it is larger than the sum of its proper divisors (1).
12400203111427 is an equidigital number, since it uses as much as digits as its factorization.
12400203111427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 12400203111427 its reverse (72411130200421), we get a palindrome (84811333311848).
The spelling of 12400203111427 in words is "twelve trillion, four hundred billion, two hundred three million, one hundred eleven thousand, four hundred twenty-seven".
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