Base | Representation |
---|---|
bin | 1011010001110010010110… |
… | …1100111001110000011011 |
3 | 1121220110002110211121022121 |
4 | 2310130211230321300123 |
5 | 3111131103444031301 |
6 | 42212324043402111 |
7 | 2416612410230131 |
oct | 264344554716033 |
9 | 47813073747277 |
10 | 12400203111451 |
11 | 3a50995424901 |
12 | 14832aab23337 |
13 | 6bc4461344cc |
14 | 30c25cb33751 |
15 | 16785758a3a1 |
hex | b4725b39c1b |
12400203111451 has 2 divisors, whose sum is σ = 12400203111452. Its totient is φ = 12400203111450.
The previous prime is 12400203111427. The next prime is 12400203111467. The reversal of 12400203111451 is 15411130200421.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12400203111451 - 213 = 12400203103259 is a prime.
It is not a weakly prime, because it can be changed into another prime (12400203111151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200101555725 + 6200101555726.
It is an arithmetic number, because the mean of its divisors is an integer number (6200101555726).
Almost surely, 212400203111451 is an apocalyptic number.
12400203111451 is a deficient number, since it is larger than the sum of its proper divisors (1).
12400203111451 is an equidigital number, since it uses as much as digits as its factorization.
12400203111451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 12400203111451 its reverse (15411130200421), we get a palindrome (27811333311872).
The spelling of 12400203111451 in words is "twelve trillion, four hundred billion, two hundred three million, one hundred eleven thousand, four hundred fifty-one".
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