1240041411131 has 2 divisors, whose sum is σ = 1240041411132. Its totient is φ = 1240041411130.

The previous prime is 1240041411067. The next prime is 1240041411163. The reversal of 1240041411131 is 1311141400421.

It is a strong prime.

It is an emirp because it is prime and its reverse (1311141400421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1240041411131 - 2⁶ = 1240041411067 is a prime.

It is a super-2 number, since 2×1240041411131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1240041411097 and 1240041411106.

It is not a weakly prime, because it can be changed into another prime (1240041410131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620020705565 + 620020705566.

It is an arithmetic number, because the mean of its divisors is an integer number (620020705566).

Almost surely, 2^{1240041411131} is an apocalyptic number.

1240041411131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240041411131 is an equidigital number, since it uses as much as digits as its factorization.

1240041411131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1240041411131 its reverse (1311141400421), we get a palindrome (2551182811552).

The spelling of 1240041411131 in words is "one trillion, two hundred forty billion, forty-one million, four hundred eleven thousand, one hundred thirty-one".