Base | Representation |
---|---|
bin | 10010000010111000001… |
… | …111000111100111001011 |
3 | 11101112202121221201120011 |
4 | 102002320033013213023 |
5 | 130304101114133311 |
6 | 2345400042012351 |
7 | 155406246165451 |
oct | 22027017074713 |
9 | 4345677851504 |
10 | 1240041552331 |
11 | 438998145aaa |
12 | 1803b34a70b7 |
13 | 8cc2115853a |
14 | 440384309d1 |
15 | 223ca17e321 |
hex | 120b83c79cb |
1240041552331 has 2 divisors, whose sum is σ = 1240041552332. Its totient is φ = 1240041552330.
The previous prime is 1240041552329. The next prime is 1240041552401. The reversal of 1240041552331 is 1332551400421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1240041552331 - 21 = 1240041552329 is a prime.
It is a super-2 number, since 2×12400415523312 (a number of 25 digits) contains 22 as substring.
Together with 1240041552329, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1240041552293 and 1240041552302.
It is not a weakly prime, because it can be changed into another prime (1240045552331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620020776165 + 620020776166.
It is an arithmetic number, because the mean of its divisors is an integer number (620020776166).
Almost surely, 21240041552331 is an apocalyptic number.
1240041552331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240041552331 is an equidigital number, since it uses as much as digits as its factorization.
1240041552331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1240041552331 its reverse (1332551400421), we get a palindrome (2572592952752).
The spelling of 1240041552331 in words is "one trillion, two hundred forty billion, forty-one million, five hundred fifty-two thousand, three hundred thirty-one".
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