Base | Representation |
---|---|
bin | 10111000110001111… |
… | …10111100000000011 |
3 | 1012000012120212010122 |
4 | 23203013313200003 |
5 | 200344002044323 |
6 | 5410252050455 |
7 | 616202605313 |
oct | 134307674003 |
9 | 35005525118 |
10 | 12400424963 |
11 | 52937978a3 |
12 | 24a0a63a2b |
13 | 12280c4684 |
14 | 858c93443 |
15 | 4c89b9ec8 |
hex | 2e31f7803 |
12400424963 has 4 divisors (see below), whose sum is σ = 12664263840. Its totient is φ = 12136586088.
The previous prime is 12400424957. The next prime is 12400424989. The reversal of 12400424963 is 36942400421.
12400424963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12400424963 - 26 = 12400424899 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12400424863) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131919368 + ... + 131919461.
It is an arithmetic number, because the mean of its divisors is an integer number (3166065960).
Almost surely, 212400424963 is an apocalyptic number.
12400424963 is a deficient number, since it is larger than the sum of its proper divisors (263838877).
12400424963 is an equidigital number, since it uses as much as digits as its factorization.
12400424963 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 263838876.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 12400424963 in words is "twelve billion, four hundred million, four hundred twenty-four thousand, nine hundred sixty-three".
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