Base | Representation |
---|---|
bin | 10010000010111000010… |
… | …110001101011010011111 |
3 | 11101112202202110011022120 |
4 | 102002320112031122133 |
5 | 130304102103123403 |
6 | 2345400145514023 |
7 | 155406301036560 |
oct | 22027026153237 |
9 | 4345682404276 |
10 | 1240043411103 |
11 | 4389991a5582 |
12 | 1803b4042913 |
13 | 8cc216595c3 |
14 | 44038796167 |
15 | 223ca3e9e53 |
hex | 120b858d69f |
1240043411103 has 8 divisors (see below), whose sum is σ = 1889589959808. Its totient is φ = 708596234904.
The previous prime is 1240043411093. The next prime is 1240043411111. The reversal of 1240043411103 is 3011143400421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1240043411103 - 214 = 1240043394719 is a prime.
It is a super-2 number, since 2×12400434111032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1240043411153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29524843101 + ... + 29524843142.
It is an arithmetic number, because the mean of its divisors is an integer number (236198744976).
Almost surely, 21240043411103 is an apocalyptic number.
1240043411103 is a deficient number, since it is larger than the sum of its proper divisors (649546548705).
1240043411103 is an equidigital number, since it uses as much as digits as its factorization.
1240043411103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59049686253.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1240043411103 its reverse (3011143400421), we get a palindrome (4251186811524).
The spelling of 1240043411103 in words is "one trillion, two hundred forty billion, forty-three million, four hundred eleven thousand, one hundred three".
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