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1240113230221 is a prime number
BaseRepresentation
bin10010000010111100100…
…000100011000110001101
311101112221121211100010211
4102002330200203012031
5130304222441331341
62345411122202421
7155411106351055
oct22027440430615
94345847740124
101240113230221
11438a24652728
121804134b3411
138cc32c639a8
1444043b6c565
15223d15dc181
hex120bc82318d

1240113230221 has 2 divisors, whose sum is σ = 1240113230222. Its totient is φ = 1240113230220.

The previous prime is 1240113230189. The next prime is 1240113230227. The reversal of 1240113230221 is 1220323110421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1147201655625 + 92911574596 = 1071075^2 + 304814^2 .

It is a cyclic number.

It is not a de Polignac number, because 1240113230221 - 25 = 1240113230189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1240113230192 and 1240113230201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240113230227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620056615110 + 620056615111.

It is an arithmetic number, because the mean of its divisors is an integer number (620056615111).

Almost surely, 21240113230221 is an apocalyptic number.

It is an amenable number.

1240113230221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240113230221 is an equidigital number, since it uses as much as digits as its factorization.

1240113230221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1240113230221 its reverse (1220323110421), we get a palindrome (2460436340642).

The spelling of 1240113230221 in words is "one trillion, two hundred forty billion, one hundred thirteen million, two hundred thirty thousand, two hundred twenty-one".