124011450133 has 4 divisors (see below), whose sum is σ = 124013020768. Its totient is φ = 124009879500.

The previous prime is 124011450109. The next prime is 124011450161. The reversal of 124011450133 is 331054110421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 331054110421 = 5273 ⋅62782877.

It is a cyclic number.

It is not a de Polignac number, because 124011450133 - 2⁹ = 124011449621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 124011450098 and 124011450107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (124011450833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 660243 + ... + 827008.

It is an arithmetic number, because the mean of its divisors is an integer number (31003255192).

Almost surely, 2^124011450133 is an apocalyptic number.

It is an amenable number.

124011450133 is a deficient number, since it is larger than the sum of its proper divisors (1570635).

124011450133 is an equidigital number, since it uses as much as digits as its factorization.

124011450133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1570634.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 124011450133 its reverse (331054110421), we get a palindrome (455065560554).

The spelling of 124011450133 in words is "one hundred twenty-four billion, eleven million, four hundred fifty thousand, one hundred thirty-three".