Base | Representation |
---|---|
bin | 10010000010111101101… |
… | …000111111110101110001 |
3 | 11101112222221120020101221 |
4 | 102002331220333311301 |
5 | 130304242322103241 |
6 | 2345413041225041 |
7 | 155411426651446 |
oct | 22027550776561 |
9 | 4345887506357 |
10 | 1240132222321 |
11 | 438a34344783 |
12 | 180419932181 |
13 | 8cc36b83415 |
14 | 440464b39cd |
15 | 223d30de5d1 |
hex | 120bda3fd71 |
1240132222321 has 2 divisors, whose sum is σ = 1240132222322. Its totient is φ = 1240132222320.
The previous prime is 1240132222253. The next prime is 1240132222333. The reversal of 1240132222321 is 1232222310421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 987163460721 + 252968761600 = 993561^2 + 502960^2 .
It is a cyclic number.
It is not a de Polignac number, because 1240132222321 - 213 = 1240132214129 is a prime.
It is not a weakly prime, because it can be changed into another prime (1240132222361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620066111160 + 620066111161.
It is an arithmetic number, because the mean of its divisors is an integer number (620066111161).
Almost surely, 21240132222321 is an apocalyptic number.
It is an amenable number.
1240132222321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240132222321 is an equidigital number, since it uses as much as digits as its factorization.
1240132222321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1240132222321 its reverse (1232222310421), we get a palindrome (2472354532742).
The spelling of 1240132222321 in words is "one trillion, two hundred forty billion, one hundred thirty-two million, two hundred twenty-two thousand, three hundred twenty-one".
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