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12401333001131 is a prime number
BaseRepresentation
bin1011010001110110100100…
…0011000101101110101011
31121220120000012220221120112
42310131221003011232223
53111140412222014011
642213032125044535
72416652410152134
oct264355103055653
947816005827515
1012401333001131
113a514151a4728
1214835653b674b
136bc59624bb99
1430c328c12c8b
151678c187758b
hexb47690c5bab

12401333001131 has 2 divisors, whose sum is σ = 12401333001132. Its totient is φ = 12401333001130.

The previous prime is 12401333001121. The next prime is 12401333001181. The reversal of 12401333001131 is 13110033310421.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12401333001131 - 218 = 12401332738987 is a prime.

It is a super-2 number, since 2×124013330011312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12401333001097 and 12401333001106.

It is not a weakly prime, because it can be changed into another prime (12401333001121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200666500565 + 6200666500566.

It is an arithmetic number, because the mean of its divisors is an integer number (6200666500566).

Almost surely, 212401333001131 is an apocalyptic number.

12401333001131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12401333001131 is an equidigital number, since it uses as much as digits as its factorization.

12401333001131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 12401333001131 its reverse (13110033310421), we get a palindrome (25511366311552).

The spelling of 12401333001131 in words is "twelve trillion, four hundred one billion, three hundred thirty-three million, one thousand, one hundred thirty-one".