Base | Representation |
---|---|
bin | 10111000110010110… |
… | …10101010001101001 |
3 | 1012000021022000012201 |
4 | 23203023111101221 |
5 | 200344220131403 |
6 | 5410323340201 |
7 | 616213410553 |
oct | 134313252151 |
9 | 35007260181 |
10 | 12401333353 |
11 | 5294258332 |
12 | 24a1221661 |
13 | 1228351c96 |
14 | 85904c4d3 |
15 | 4c8ae921d |
hex | 2e32d5469 |
12401333353 has 2 divisors, whose sum is σ = 12401333354. Its totient is φ = 12401333352.
The previous prime is 12401333299. The next prime is 12401333363. The reversal of 12401333353 is 35333310421.
12401333353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7213444624 + 5187888729 = 84932^2 + 72027^2 .
It is a cyclic number.
It is not a de Polignac number, because 12401333353 - 29 = 12401332841 is a prime.
It is not a weakly prime, because it can be changed into another prime (12401333363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200666676 + 6200666677.
It is an arithmetic number, because the mean of its divisors is an integer number (6200666677).
Almost surely, 212401333353 is an apocalyptic number.
It is an amenable number.
12401333353 is a deficient number, since it is larger than the sum of its proper divisors (1).
12401333353 is an equidigital number, since it uses as much as digits as its factorization.
12401333353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 28.
Adding to 12401333353 its reverse (35333310421), we get a palindrome (47734643774).
The spelling of 12401333353 in words is "twelve billion, four hundred one million, three hundred thirty-three thousand, three hundred fifty-three".
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