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1240134133 = 7177162019
BaseRepresentation
bin100100111101010…
…1111000111110101
310012102112100012211
41021322233013311
510014433243013
6323020213421
742505652260
oct11172570765
93172470184
101240134133
11587029147
122a739a271
13169c070a4
14ba9b9cd7
1573d1723d
hex49eaf1f5

1240134133 has 4 divisors (see below), whose sum is σ = 1417296160. Its totient is φ = 1062972108.

The previous prime is 1240134131. The next prime is 1240134169. The reversal of 1240134133 is 3314310421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1240134133 - 21 = 1240134131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1240134131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88581003 + ... + 88581016.

It is an arithmetic number, because the mean of its divisors is an integer number (354324040).

Almost surely, 21240134133 is an apocalyptic number.

It is an amenable number.

1240134133 is a deficient number, since it is larger than the sum of its proper divisors (177162027).

1240134133 is an equidigital number, since it uses as much as digits as its factorization.

1240134133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 177162026.

The product of its (nonzero) digits is 864, while the sum is 22.

The square root of 1240134133 is about 35215.5382324337. The cubic root of 1240134133 is about 1074.3758072413.

Adding to 1240134133 its reverse (3314310421), we get a palindrome (4554444554).

The spelling of 1240134133 in words is "one billion, two hundred forty million, one hundred thirty-four thousand, one hundred thirty-three".

Divisors: 1 7 177162019 1240134133