124014240113 has 4 divisors (see below), whose sum is σ = 124034606448. Its totient is φ = 123993873780.

The previous prime is 124014240071. The next prime is 124014240157. The reversal of 124014240113 is 311042410421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 124014240113 - 2¹⁶ = 124014174577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (124014240173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10174031 + ... + 10186212.

It is an arithmetic number, because the mean of its divisors is an integer number (31008651612).

Almost surely, 2^124014240113 is an apocalyptic number.

It is an amenable number.

124014240113 is a deficient number, since it is larger than the sum of its proper divisors (20366335).

124014240113 is an equidigital number, since it uses as much as digits as its factorization.

124014240113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20366334.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 124014240113 its reverse (311042410421), we get a palindrome (435056650534).

The spelling of 124014240113 in words is "one hundred twenty-four billion, fourteen million, two hundred forty thousand, one hundred thirteen".