Base | Representation |
---|---|
bin | 10111000110010111… |
… | …01101001011001001 |
3 | 1012000021110222111012 |
4 | 23203023231023021 |
5 | 200344231244431 |
6 | 5410325413305 |
7 | 616214266133 |
oct | 134313551311 |
9 | 35007428435 |
10 | 12401431241 |
11 | 5294314931 |
12 | 24a126a235 |
13 | 12283876c4 |
14 | 859076053 |
15 | 4c8b1822b |
hex | 2e32ed2c9 |
12401431241 has 4 divisors (see below), whose sum is σ = 12402782484. Its totient is φ = 12400080000.
The previous prime is 12401431199. The next prime is 12401431307. The reversal of 12401431241 is 14213410421.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11889721600 + 511709641 = 109040^2 + 22621^2 .
It is a cyclic number.
It is not a de Polignac number, because 12401431241 - 218 = 12401169097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12401437241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 661760 + ... + 680241.
It is an arithmetic number, because the mean of its divisors is an integer number (3100695621).
Almost surely, 212401431241 is an apocalyptic number.
It is an amenable number.
12401431241 is a deficient number, since it is larger than the sum of its proper divisors (1351243).
12401431241 is an equidigital number, since it uses as much as digits as its factorization.
12401431241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1351242.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 12401431241 its reverse (14213410421), we get a palindrome (26614841662).
The spelling of 12401431241 in words is "twelve billion, four hundred one million, four hundred thirty-one thousand, two hundred forty-one".
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