Base | Representation |
---|---|
bin | 10010000010111110010… |
… | …011101101111111100011 |
3 | 11101120000201122012200001 |
4 | 102002332103231333203 |
5 | 130304303203441121 |
6 | 2345414121240431 |
7 | 155411624104036 |
oct | 22027623557743 |
9 | 4346021565601 |
10 | 1240143421411 |
11 | 438a3a6a3824 |
12 | 180421633117 |
13 | 8cc392a49bb |
14 | 44047b8b01d |
15 | 223d40a2991 |
hex | 120be4edfe3 |
1240143421411 has 2 divisors, whose sum is σ = 1240143421412. Its totient is φ = 1240143421410.
The previous prime is 1240143421397. The next prime is 1240143421441. The reversal of 1240143421411 is 1141243410421.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1240143421411 - 213 = 1240143413219 is a prime.
It is a super-2 number, since 2×12401434214112 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1240143421411.
It is not a weakly prime, because it can be changed into another prime (1240143421441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620071710705 + 620071710706.
It is an arithmetic number, because the mean of its divisors is an integer number (620071710706).
Almost surely, 21240143421411 is an apocalyptic number.
1240143421411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240143421411 is an equidigital number, since it uses as much as digits as its factorization.
1240143421411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 1240143421411 its reverse (1141243410421), we get a palindrome (2381386831832).
The spelling of 1240143421411 in words is "one trillion, two hundred forty billion, one hundred forty-three million, four hundred twenty-one thousand, four hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •