Base | Representation |
---|---|
bin | 10010000010111110010… |
… | …101001101100100110101 |
3 | 11101120000202101002201021 |
4 | 102002332111031210311 |
5 | 130304303304003132 |
6 | 2345414133501141 |
7 | 155411630324332 |
oct | 22027625154465 |
9 | 4346022332637 |
10 | 1240143812917 |
11 | 438a3a940989 |
12 | 1804217a17b1 |
13 | 8cc393b0c69 |
14 | 44047c4d989 |
15 | 223d412d997 |
hex | 120be54d935 |
1240143812917 has 2 divisors, whose sum is σ = 1240143812918. Its totient is φ = 1240143812916.
The previous prime is 1240143812909. The next prime is 1240143812959. The reversal of 1240143812917 is 7192183410421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 843588977841 + 396554835076 = 918471^2 + 629726^2 .
It is a cyclic number.
It is not a de Polignac number, because 1240143812917 - 23 = 1240143812909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1240143812977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620071906458 + 620071906459.
It is an arithmetic number, because the mean of its divisors is an integer number (620071906459).
Almost surely, 21240143812917 is an apocalyptic number.
It is an amenable number.
1240143812917 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240143812917 is an equidigital number, since it uses as much as digits as its factorization.
1240143812917 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 43.
The spelling of 1240143812917 in words is "one trillion, two hundred forty billion, one hundred forty-three million, eight hundred twelve thousand, nine hundred seventeen".
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