Base | Representation |
---|---|
bin | 10010000010111110101… |
… | …101100101000011100111 |
3 | 11101120001012101121220022 |
4 | 102002332231211003213 |
5 | 130304311422404201 |
6 | 2345414522425355 |
7 | 155412035530223 |
oct | 22027655450347 |
9 | 4346035347808 |
10 | 1240150200551 |
11 | 438a43504019 |
12 | 18042396225b |
13 | 8cc3a809522 |
14 | 44048a33783 |
15 | 223d499141b |
hex | 120beb650e7 |
1240150200551 has 16 divisors (see below), whose sum is σ = 1345488408000. Its totient is φ = 1139512163328.
The previous prime is 1240150200529. The next prime is 1240150200631. The reversal of 1240150200551 is 1550020510421.
It is a cyclic number.
It is not a de Polignac number, because 1240150200551 - 214 = 1240150184167 is a prime.
It is a super-3 number, since 3×12401502005513 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1240150200551.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1240150230551) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4587626 + ... + 4850423.
It is an arithmetic number, because the mean of its divisors is an integer number (84093025500).
Almost surely, 21240150200551 is an apocalyptic number.
1240150200551 is a deficient number, since it is larger than the sum of its proper divisors (105338207449).
1240150200551 is a wasteful number, since it uses less digits than its factorization.
1240150200551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9438298.
The product of its (nonzero) digits is 2000, while the sum is 26.
Adding to 1240150200551 its reverse (1550020510421), we get a palindrome (2790170710972).
The spelling of 1240150200551 in words is "one trillion, two hundred forty billion, one hundred fifty million, two hundred thousand, five hundred fifty-one".
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