Base | Representation |
---|---|
bin | 111001110000000101… |
… | …0110101111110101101 |
3 | 102212010011112221122002 |
4 | 1303200022311332231 |
5 | 4012443111220323 |
6 | 132550215302045 |
7 | 11650221542462 |
oct | 1634012657655 |
9 | 385104487562 |
10 | 124020023213 |
11 | 48662085059 |
12 | 2005207a925 |
13 | b905cc9928 |
14 | 60071cd669 |
15 | 335cd83828 |
hex | 1ce02b5fad |
124020023213 has 2 divisors, whose sum is σ = 124020023214. Its totient is φ = 124020023212.
The previous prime is 124020023111. The next prime is 124020023243. The reversal of 124020023213 is 312320020421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 70159825129 + 53860198084 = 264877^2 + 232078^2 .
It is a cyclic number.
It is not a de Polignac number, because 124020023213 - 218 = 124019761069 is a prime.
It is a super-3 number, since 3×1240200232133 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124020023243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62010011606 + 62010011607.
It is an arithmetic number, because the mean of its divisors is an integer number (62010011607).
Almost surely, 2124020023213 is an apocalyptic number.
It is an amenable number.
124020023213 is a deficient number, since it is larger than the sum of its proper divisors (1).
124020023213 is an equidigital number, since it uses as much as digits as its factorization.
124020023213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 124020023213 its reverse (312320020421), we get a palindrome (436340043634).
The spelling of 124020023213 in words is "one hundred twenty-four billion, twenty million, twenty-three thousand, two hundred thirteen".
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