Search a number
-
+
1240201355 = 58312723531
BaseRepresentation
bin100100111101011…
…1111100010001011
310012102122202102112
41021322333202023
510014442420410
6323021452535
742506352251
oct11172774213
93172582375
101240201355
115870746a8
122a741114b
13169c2b873
14ba9d65d1
1573d2c105
hex49ebf88b

1240201355 has 16 divisors (see below), whose sum is σ = 1518096384. Its totient is φ = 972447840.

The previous prime is 1240201337. The next prime is 1240201373. The reversal of 1240201355 is 5531020421.

It is an interprime number because it is at equal distance from previous prime (1240201337) and next prime (1240201373).

It is not a de Polignac number, because 1240201355 - 28 = 1240201099 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1240201355.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40940 + ... + 64470.

It is an arithmetic number, because the mean of its divisors is an integer number (94881024).

Almost surely, 21240201355 is an apocalyptic number.

1240201355 is a deficient number, since it is larger than the sum of its proper divisors (277895029).

1240201355 is a wasteful number, since it uses less digits than its factorization.

1240201355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23746.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 1240201355 is about 35216.4926561405. The cubic root of 1240201355 is about 1074.3952192236.

Adding to 1240201355 its reverse (5531020421), we get a palindrome (6771221776).

The spelling of 1240201355 in words is "one billion, two hundred forty million, two hundred one thousand, three hundred fifty-five".

Divisors: 1 5 83 127 415 635 10541 23531 52705 117655 1953073 2988437 9765365 14942185 248040271 1240201355