Base | Representation |
---|---|
bin | 10111000110011101… |
… | …01101110010110101 |
3 | 1012000022222001202101 |
4 | 23203032231302311 |
5 | 200344432021323 |
6 | 5410354342101 |
7 | 616224063265 |
oct | 134316556265 |
9 | 35008861671 |
10 | 12402220213 |
11 | 5294803679 |
12 | 24a158a931 |
13 | 12285a2856 |
14 | 8591dd7a5 |
15 | 4c8c21dad |
hex | 2e33adcb5 |
12402220213 has 2 divisors, whose sum is σ = 12402220214. Its totient is φ = 12402220212.
The previous prime is 12402220157. The next prime is 12402220223. The reversal of 12402220213 is 31202220421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12388135204 + 14085009 = 111302^2 + 3753^2 .
It is a cyclic number.
It is not a de Polignac number, because 12402220213 - 213 = 12402212021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12402220223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201110106 + 6201110107.
It is an arithmetic number, because the mean of its divisors is an integer number (6201110107).
Almost surely, 212402220213 is an apocalyptic number.
It is an amenable number.
12402220213 is a deficient number, since it is larger than the sum of its proper divisors (1).
12402220213 is an equidigital number, since it uses as much as digits as its factorization.
12402220213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 12402220213 its reverse (31202220421), we get a palindrome (43604440634).
The spelling of 12402220213 in words is "twelve billion, four hundred two million, two hundred twenty thousand, two hundred thirteen".
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