Base | Representation |
---|---|
bin | 1011010001111001110111… |
… | …1111010110010101000001 |
3 | 1121220122022010020210012011 |
4 | 2310132131333112111001 |
5 | 3111144222112303433 |
6 | 42213300214332521 |
7 | 2420013413633113 |
oct | 264363577262501 |
9 | 47818263223164 |
10 | 12402221212993 |
11 | 3a51830605417 |
12 | 148377295a141 |
13 | 6bc6a8278b31 |
14 | 30c3b0b813b3 |
15 | 1679248263cd |
hex | b479dfd6541 |
12402221212993 has 2 divisors, whose sum is σ = 12402221212994. Its totient is φ = 12402221212992.
The previous prime is 12402221212991. The next prime is 12402221213069. The reversal of 12402221212993 is 39921212220421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11212097311809 + 1190123901184 = 3348447^2 + 1090928^2 .
It is a cyclic number.
It is not a de Polignac number, because 12402221212993 - 21 = 12402221212991 is a prime.
Together with 12402221212991, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12402221212991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201110606496 + 6201110606497.
It is an arithmetic number, because the mean of its divisors is an integer number (6201110606497).
Almost surely, 212402221212993 is an apocalyptic number.
It is an amenable number.
12402221212993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12402221212993 is an equidigital number, since it uses as much as digits as its factorization.
12402221212993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 40.
The spelling of 12402221212993 in words is "twelve trillion, four hundred two billion, two hundred twenty-one million, two hundred twelve thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •