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124024041113 = 717717720159
BaseRepresentation
bin111001110000001101…
…0001010111010011001
3102212010110010002011012
41303200122022322121
54013000123303423
6132550441343305
711650300645460
oct1634032127231
9385113102135
10124024041113
1148664379835
1220053497b35
13b906aa569b
1460079579d7
15335d3c9078
hex1ce068ae99

124024041113 has 4 divisors (see below), whose sum is σ = 141741761280. Its totient is φ = 106306320948.

The previous prime is 124024041073. The next prime is 124024041139. The reversal of 124024041113 is 311140420421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 124024041113 - 26 = 124024041049 is a prime.

It is a super-2 number, since 2×1240240411132 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (124024041313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8858860073 + ... + 8858860086.

It is an arithmetic number, because the mean of its divisors is an integer number (35435440320).

Almost surely, 2124024041113 is an apocalyptic number.

It is an amenable number.

124024041113 is a deficient number, since it is larger than the sum of its proper divisors (17717720167).

124024041113 is an equidigital number, since it uses as much as digits as its factorization.

124024041113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17717720166.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 124024041113 its reverse (311140420421), we get a palindrome (435164461534).

The spelling of 124024041113 in words is "one hundred twenty-four billion, twenty-four million, forty-one thousand, one hundred thirteen".

Divisors: 1 7 17717720159 124024041113