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12402423011053 is a prime number
BaseRepresentation
bin1011010001111010101000…
…0001001001011011101101
31121220122211011222012002101
42310132222001021123231
53111200130242323203
642213332223455101
72420021414116465
oct264365201113355
947818734865071
1012402423011053
113a51924506279
12148380a457491
136bc70b01267a
1430c3cd8b0ba5
151679373d841d
hexb47aa0496ed

12402423011053 has 2 divisors, whose sum is σ = 12402423011054. Its totient is φ = 12402423011052.

The previous prime is 12402423010993. The next prime is 12402423011071. The reversal of 12402423011053 is 35011032420421.

12402423011053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12294153715204 + 108269295849 = 3506302^2 + 329043^2 .

It is a cyclic number.

It is not a de Polignac number, because 12402423011053 - 217 = 12402422879981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12402423012053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201211505526 + 6201211505527.

It is an arithmetic number, because the mean of its divisors is an integer number (6201211505527).

Almost surely, 212402423011053 is an apocalyptic number.

It is an amenable number.

12402423011053 is a deficient number, since it is larger than the sum of its proper divisors (1).

12402423011053 is an equidigital number, since it uses as much as digits as its factorization.

12402423011053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 12402423011053 its reverse (35011032420421), we get a palindrome (47413455431474).

The spelling of 12402423011053 in words is "twelve trillion, four hundred two billion, four hundred twenty-three million, eleven thousand, fifty-three".