Base | Representation |
---|---|
bin | 1011010001111011100001… |
… | …0111100111010010110011 |
3 | 1121220200102222000121010101 |
4 | 2310132320113213102303 |
5 | 3111201123412002210 |
6 | 42213412144213231 |
7 | 2420030366461345 |
oct | 264367027472263 |
9 | 47820388017111 |
10 | 12402663781555 |
11 | 3a51a38405763 |
12 | 148387700a217 |
13 | 6bc748b73118 |
14 | 30c413867295 |
15 | 16794d5e7a3a |
hex | b47b85e74b3 |
12402663781555 has 4 divisors (see below), whose sum is σ = 14883196537872. Its totient is φ = 9922131025240.
The previous prime is 12402663781537. The next prime is 12402663781567. The reversal of 12402663781555 is 55518736620421.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 12402663781555 - 211 = 12402663779507 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12402663781496 and 12402663781505.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1240266378151 + ... + 1240266378160.
It is an arithmetic number, because the mean of its divisors is an integer number (3720799134468).
Almost surely, 212402663781555 is an apocalyptic number.
12402663781555 is a deficient number, since it is larger than the sum of its proper divisors (2480532756317).
12402663781555 is an equidigital number, since it uses as much as digits as its factorization.
12402663781555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2480532756316.
The product of its (nonzero) digits is 12096000, while the sum is 55.
The spelling of 12402663781555 in words is "twelve trillion, four hundred two billion, six hundred sixty-three million, seven hundred eighty-one thousand, five hundred fifty-five".
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