Base | Representation |
---|---|
bin | 1011010001111101011000… |
… | …1100000010101001100001 |
3 | 1121220201201211101121002220 |
4 | 2310133112030002221201 |
5 | 3111203140000024403 |
6 | 42213533535101253 |
7 | 2420045653013646 |
oct | 264372614025141 |
9 | 47821654347086 |
10 | 12403164064353 |
11 | 3a52174845617 |
12 | 1483996671829 |
13 | 6bc7c86c6b4a |
14 | 30c460093dcd |
15 | 16797c4b9953 |
hex | b47d6302a61 |
12403164064353 has 4 divisors (see below), whose sum is σ = 16537552085808. Its totient is φ = 8268776042900.
The previous prime is 12403164064349. The next prime is 12403164064481. The reversal of 12403164064353 is 35346046130421.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12403164064353 - 22 = 12403164064349 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12403164064553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2067194010723 + ... + 2067194010728.
It is an arithmetic number, because the mean of its divisors is an integer number (4134388021452).
Almost surely, 212403164064353 is an apocalyptic number.
It is an amenable number.
12403164064353 is a deficient number, since it is larger than the sum of its proper divisors (4134388021455).
12403164064353 is an equidigital number, since it uses as much as digits as its factorization.
12403164064353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4134388021454.
The product of its (nonzero) digits is 622080, while the sum is 42.
The spelling of 12403164064353 in words is "twelve trillion, four hundred three billion, one hundred sixty-four million, sixty-four thousand, three hundred fifty-three".
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