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4134388021451 is a prime number
BaseRepresentation
bin111100001010011100101…
…110101011100011001011
3112122020120121110112100222
4330022130232223203023
51020214211313141301
612443151151420255
7604461663225662
oct74123456534313
915566517415328
104134388021451
111354425289206
1256933222468b
1323cb42acac5c
141041694c5dd9
157282918d31b
hex3c29cbab8cb

4134388021451 has 2 divisors, whose sum is σ = 4134388021452. Its totient is φ = 4134388021450.

The previous prime is 4134388021447. The next prime is 4134388021453. The reversal of 4134388021451 is 1541208834314.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4134388021451 - 22 = 4134388021447 is a prime.

It is a super-2 number, since 2×41343880214512 (a number of 26 digits) contains 22 as substring.

Together with 4134388021453, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4134388021453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067194010725 + 2067194010726.

It is an arithmetic number, because the mean of its divisors is an integer number (2067194010726).

Almost surely, 24134388021451 is an apocalyptic number.

4134388021451 is a deficient number, since it is larger than the sum of its proper divisors (1).

4134388021451 is an equidigital number, since it uses as much as digits as its factorization.

4134388021451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 368640, while the sum is 44.

The spelling of 4134388021451 in words is "four trillion, one hundred thirty-four billion, three hundred eighty-eight million, twenty-one thousand, four hundred fifty-one".