12403214315351 has 4 divisors (see below), whose sum is σ = 12738436323912. Its totient is φ = 12067992306792.

The previous prime is 12403214315299. The next prime is 12403214315413. The reversal of 12403214315351 is 15351341230421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12403214315351 - 2¹⁰ = 12403214314327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12403214365351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167611004225 + ... + 167611004298.

It is an arithmetic number, because the mean of its divisors is an integer number (3184609080978).

Almost surely, 2^{12403214315351} is an apocalyptic number.

12403214315351 is a deficient number, since it is larger than the sum of its proper divisors (335222008561).

12403214315351 is an equidigital number, since it uses as much as digits as its factorization.

12403214315351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 335222008560.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 12403214315351 its reverse (15351341230421), we get a palindrome (27754555545772).

The spelling of 12403214315351 in words is "twelve trillion, four hundred three billion, two hundred fourteen million, three hundred fifteen thousand, three hundred fifty-one".