Base | Representation |
---|---|
bin | 1011010001111101101001… |
… | …0000011110010011001011 |
3 | 1121220201220120212002220021 |
4 | 2310133122100132103023 |
5 | 3111203304434210201 |
6 | 42213544414241311 |
7 | 2420050442215615 |
oct | 264373220362313 |
9 | 47821816762807 |
10 | 12403232335051 |
11 | 3a521aa335388 |
12 | 14839b54b6237 |
13 | 6bc8098ab4cc |
14 | 30c469185db5 |
15 | 1679834a2ea1 |
hex | b47da41e4cb |
12403232335051 has 2 divisors, whose sum is σ = 12403232335052. Its totient is φ = 12403232335050.
The previous prime is 12403232335027. The next prime is 12403232335079. The reversal of 12403232335051 is 15053323230421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12403232335051 - 27 = 12403232334923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12403232334998 and 12403232335016.
It is not a weakly prime, because it can be changed into another prime (12403232339051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201616167525 + 6201616167526.
It is an arithmetic number, because the mean of its divisors is an integer number (6201616167526).
Almost surely, 212403232335051 is an apocalyptic number.
12403232335051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12403232335051 is an equidigital number, since it uses as much as digits as its factorization.
12403232335051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 12403232335051 its reverse (15053323230421), we get a palindrome (27456555565472).
The spelling of 12403232335051 in words is "twelve trillion, four hundred three billion, two hundred thirty-two million, three hundred thirty-five thousand, fifty-one".
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