Base | Representation |
---|---|
bin | 10010000011001001100… |
… | …100010100001010100101 |
3 | 11101120111220002022210121 |
4 | 102003021210110022211 |
5 | 130310200033241240 |
6 | 2345444550121541 |
7 | 155416406531020 |
oct | 22031144241245 |
9 | 4346456068717 |
10 | 1240332321445 |
11 | 439027295158 |
12 | 1804749502b1 |
13 | 8cc69473879 |
14 | 44064cc01b7 |
15 | 223e596804a |
hex | 120c99142a5 |
1240332321445 has 16 divisors (see below), whose sum is σ = 1728912878208. Its totient is φ = 836570744640.
The previous prime is 1240332321409. The next prime is 1240332321461. The reversal of 1240332321445 is 5441232330421.
It is not a de Polignac number, because 1240332321445 - 217 = 1240332190373 is a prime.
It is a super-2 number, since 2×12403323214452 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1240332321445.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 290473819 + ... + 290478088.
It is an arithmetic number, because the mean of its divisors is an integer number (108057054888).
Almost surely, 21240332321445 is an apocalyptic number.
It is an amenable number.
1240332321445 is a deficient number, since it is larger than the sum of its proper divisors (488580556763).
1240332321445 is an equidigital number, since it uses as much as digits as its factorization.
1240332321445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 580951980.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 1240332321445 its reverse (5441232330421), we get a palindrome (6681564651866).
The spelling of 1240332321445 in words is "one trillion, two hundred forty billion, three hundred thirty-two million, three hundred twenty-one thousand, four hundred forty-five".
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