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1240343123141 = 5921022764799
BaseRepresentation
bin10010000011001010001…
…101100001010011000101
311101120112122102002221102
4102003022031201103011
5130310210314420031
62345450013425445
7155416600406603
oct22031215412305
94346478362842
101240343123141
114390323a2681
1218047849b285
138cc6b7862c5
14440664d2873
15223e689d7cb
hex120ca3614c5

1240343123141 has 4 divisors (see below), whose sum is σ = 1261365888000. Its totient is φ = 1219320358284.

The previous prime is 1240343123101. The next prime is 1240343123237. The reversal of 1240343123141 is 1413213430421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1240343123141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1240343123101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10511382341 + ... + 10511382458.

It is an arithmetic number, because the mean of its divisors is an integer number (315341472000).

Almost surely, 21240343123141 is an apocalyptic number.

It is an amenable number.

1240343123141 is a deficient number, since it is larger than the sum of its proper divisors (21022764859).

1240343123141 is an equidigital number, since it uses as much as digits as its factorization.

1240343123141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21022764858.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1240343123141 its reverse (1413213430421), we get a palindrome (2653556553562).

The spelling of 1240343123141 in words is "one trillion, two hundred forty billion, three hundred forty-three million, one hundred twenty-three thousand, one hundred forty-one".

Divisors: 1 59 21022764799 1240343123141