12403754051341 has 4 divisors (see below), whose sum is σ = 12403761098400. Its totient is φ = 12403747004284.

The previous prime is 12403754051333. The next prime is 12403754051387. The reversal of 12403754051341 is 14315045730421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12403754051341 - 2³ = 12403754051333 is a prime.

It is a super-2 number, since 2×12403754051341² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12403754051294 and 12403754051303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12403754051141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1600890 + ... + 5231668.

It is an arithmetic number, because the mean of its divisors is an integer number (3100940274600).

Almost surely, 2^{12403754051341} is an apocalyptic number.

It is an amenable number.

12403754051341 is a deficient number, since it is larger than the sum of its proper divisors (7047059).

12403754051341 is an equidigital number, since it uses as much as digits as its factorization.

12403754051341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7047058.

The product of its (nonzero) digits is 201600, while the sum is 40.

Adding to 12403754051341 its reverse (14315045730421), we get a palindrome (26718799781762).

The spelling of 12403754051341 in words is "twelve trillion, four hundred three billion, seven hundred fifty-four million, fifty-one thousand, three hundred forty-one".