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1240401152503 = 6120334445123
BaseRepresentation
bin10010000011001101101…
…010111000100111110111
311101120200200121022021001
4102003031222320213313
5130310320143340003
62345455445304131
7155421203555452
oct22031552704767
94346620538231
101240401152503
11439062127a27
12180493a05047
138cc7a7c32c6
14440700ba499
15223eba1261d
hex120cdab89f7

1240401152503 has 4 divisors (see below), whose sum is σ = 1260735597688. Its totient is φ = 1220066707320.

The previous prime is 1240401152491. The next prime is 1240401152513. The reversal of 1240401152503 is 3052511040421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1240401152503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1240401152513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10167222501 + ... + 10167222622.

It is an arithmetic number, because the mean of its divisors is an integer number (315183899422).

Almost surely, 21240401152503 is an apocalyptic number.

1240401152503 is a deficient number, since it is larger than the sum of its proper divisors (20334445185).

1240401152503 is an equidigital number, since it uses as much as digits as its factorization.

1240401152503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20334445184.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 1240401152503 its reverse (3052511040421), we get a palindrome (4292912192924).

The spelling of 1240401152503 in words is "one trillion, two hundred forty billion, four hundred one million, one hundred fifty-two thousand, five hundred three".

Divisors: 1 61 20334445123 1240401152503