1240412134537 has 2 divisors, whose sum is σ = 1240412134538. Its totient is φ = 1240412134536.

The previous prime is 1240412134523. The next prime is 1240412134603. The reversal of 1240412134537 is 7354312140421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 786518885881 + 453893248656 = 886859^2 + 673716^2 .

It is a cyclic number.

It is not a de Polignac number, because 1240412134537 - 2¹⁵ = 1240412101769 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1240412134496 and 1240412134505.

It is not a weakly prime, because it can be changed into another prime (1240412131537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620206067268 + 620206067269.

It is an arithmetic number, because the mean of its divisors is an integer number (620206067269).

Almost surely, 2^{1240412134537} is an apocalyptic number.

It is an amenable number.

1240412134537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240412134537 is an equidigital number, since it uses as much as digits as its factorization.

1240412134537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80640, while the sum is 37.

Adding to 1240412134537 its reverse (7354312140421), we get a palindrome (8594724274958).

The spelling of 1240412134537 in words is "one trillion, two hundred forty billion, four hundred twelve million, one hundred thirty-four thousand, five hundred thirty-seven".