Base | Representation |
---|---|
bin | 10111000110101100… |
… | …10100001011100010 |
3 | 1012000110201021120221 |
4 | 23203112110023202 |
5 | 200400434244300 |
6 | 5410505153254 |
7 | 616250031460 |
oct | 134326241342 |
9 | 35013637527 |
10 | 12404212450 |
11 | 5295944453 |
12 | 24a218b82a |
13 | 1228b1c5a6 |
14 | 85959b830 |
15 | 4c8eb731a |
hex | 2e35942e2 |
12404212450 has 48 divisors (see below), whose sum is σ = 26520356160. Its totient is φ = 4228269120.
The previous prime is 12404212393. The next prime is 12404212459. The reversal of 12404212450 is 5421240421.
It is a super-3 number, since 3×124042124503 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (12404212459) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 41880 + ... + 162979.
It is an arithmetic number, because the mean of its divisors is an integer number (552507420).
Almost surely, 212404212450 is an apocalyptic number.
12404212450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12404212450 is an abundant number, since it is smaller than the sum of its proper divisors (14116143710).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12404212450 is a wasteful number, since it uses less digits than its factorization.
12404212450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 205051 (or 205046 counting only the distinct ones).
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 12404212450 its reverse (5421240421), we get a palindrome (17825452871).
The spelling of 12404212450 in words is "twelve billion, four hundred four million, two hundred twelve thousand, four hundred fifty".
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