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1240434127 is a prime number
BaseRepresentation
bin100100111101111…
…1000010111001111
310012110002120201201
41021323320113033
510020022343002
6323030450331
742511342012
oct11173702717
93173076651
101240434127
11587213579
122a75039a7
13169cb07ba
14baa57379
1573d76087
hex49ef85cf

1240434127 has 2 divisors, whose sum is σ = 1240434128. Its totient is φ = 1240434126.

The previous prime is 1240434079. The next prime is 1240434191. The reversal of 1240434127 is 7214340421.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1240434127 - 215 = 1240401359 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1240434095 and 1240434104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240438127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620217063 + 620217064.

It is an arithmetic number, because the mean of its divisors is an integer number (620217064).

Almost surely, 21240434127 is an apocalyptic number.

1240434127 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240434127 is an equidigital number, since it uses as much as digits as its factorization.

1240434127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 28.

The square root of 1240434127 is about 35219.7973730685. The cubic root of 1240434127 is about 1074.4624323629.

Adding to 1240434127 its reverse (7214340421), we get a palindrome (8454774548).

The spelling of 1240434127 in words is "one billion, two hundred forty million, four hundred thirty-four thousand, one hundred twenty-seven".