Base | Representation |
---|---|
bin | 10010000011010101011… |
… | …011111010010110100001 |
3 | 11101121000202202212011202 |
4 | 102003111123322112201 |
5 | 130311102022221103 |
6 | 2345520422050545 |
7 | 155424345205430 |
oct | 22032533722641 |
9 | 4347022685152 |
10 | 1240531445153 |
11 | 439119729800 |
12 | 18050b579a55 |
13 | 8cc9b7b2050 |
14 | 44083515117 |
15 | 2240819c988 |
hex | 120d56fa5a1 |
1240531445153 has 48 divisors (see below), whose sum is σ = 1689492403200. Its totient is φ = 886300652160.
The previous prime is 1240531445137. The next prime is 1240531445173. The reversal of 1240531445153 is 3515441350421.
It is not a de Polignac number, because 1240531445153 - 24 = 1240531445137 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1240531445173) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1262576 + ... + 2018702.
It is an arithmetic number, because the mean of its divisors is an integer number (35197758400).
Almost surely, 21240531445153 is an apocalyptic number.
1240531445153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1240531445153 is a deficient number, since it is larger than the sum of its proper divisors (448960958047).
1240531445153 is a wasteful number, since it uses less digits than its factorization.
1240531445153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 756318 (or 756307 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 1240531445153 its reverse (3515441350421), we get a palindrome (4755972795574).
The spelling of 1240531445153 in words is "one trillion, two hundred forty billion, five hundred thirty-one million, four hundred forty-five thousand, one hundred fifty-three".
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