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12405664436533 is a prime number
BaseRepresentation
bin1011010010000110101100…
…1110001101000100110101
31121220222012002021122220221
42310201223032031010311
53111223300043432113
642215030014454341
72420164633562524
oct264415316150465
947828162248827
1012405664436533
113a53238183205
121484373b043b1
136bcb06726804
1430c61a1a04bb
15167a76c6a98d
hexb486b38d135

12405664436533 has 2 divisors, whose sum is σ = 12405664436534. Its totient is φ = 12405664436532.

The previous prime is 12405664436519. The next prime is 12405664436579. The reversal of 12405664436533 is 33563446650421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11969122768164 + 436541668369 = 3459642^2 + 660713^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12405664436533 is a prime.

It is a super-3 number, since 3×124056644365333 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12405664436593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6202832218266 + 6202832218267.

It is an arithmetic number, because the mean of its divisors is an integer number (6202832218267).

Almost surely, 212405664436533 is an apocalyptic number.

It is an amenable number.

12405664436533 is a deficient number, since it is larger than the sum of its proper divisors (1).

12405664436533 is an equidigital number, since it uses as much as digits as its factorization.

12405664436533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18662400, while the sum is 52.

The spelling of 12405664436533 in words is "twelve trillion, four hundred five billion, six hundred sixty-four million, four hundred thirty-six thousand, five hundred thirty-three".