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124100131997 is a prime number
BaseRepresentation
bin111001110010011110…
…0011011110010011101
3102212022202021220020002
41303210330123302131
54013124113210442
6133002200304045
711652213501002
oct1634474336235
9385282256202
10124100131997
11486a331aa66
1220074a72025
13b91979768a
146013ac38a9
153364e09732
hex1ce4f1bc9d

124100131997 has 2 divisors, whose sum is σ = 124100131998. Its totient is φ = 124100131996.

The previous prime is 124100131957. The next prime is 124100132003. The reversal of 124100131997 is 799131001421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116566933561 + 7533198436 = 341419^2 + 86794^2 .

It is a cyclic number.

It is not a de Polignac number, because 124100131997 - 214 = 124100115613 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 124100131997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124100131957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62050065998 + 62050065999.

It is an arithmetic number, because the mean of its divisors is an integer number (62050065999).

Almost surely, 2124100131997 is an apocalyptic number.

It is an amenable number.

124100131997 is a deficient number, since it is larger than the sum of its proper divisors (1).

124100131997 is an equidigital number, since it uses as much as digits as its factorization.

124100131997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 38.

The spelling of 124100131997 in words is "one hundred twenty-four billion, one hundred million, one hundred thirty-one thousand, nine hundred ninety-seven".