Base | Representation |
---|---|
bin | 111001110010100001… |
… | …1101011010010000111 |
3 | 102212022212212100102221 |
4 | 1303211003223102013 |
5 | 4013130104433341 |
6 | 133002305113211 |
7 | 11652235565626 |
oct | 1634503532207 |
9 | 385285770387 |
10 | 124102030471 |
11 | 486a43a7351 |
12 | 20075628807 |
13 | b919cb0833 |
14 | 60140596bd |
15 | 3365181ed1 |
hex | 1ce50eb487 |
124102030471 has 2 divisors, whose sum is σ = 124102030472. Its totient is φ = 124102030470.
The previous prime is 124102030439. The next prime is 124102030487. The reversal of 124102030471 is 174030201421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124102030471 - 25 = 124102030439 is a prime.
It is a super-3 number, since 3×1241020304713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124102030771) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62051015235 + 62051015236.
It is an arithmetic number, because the mean of its divisors is an integer number (62051015236).
Almost surely, 2124102030471 is an apocalyptic number.
124102030471 is a deficient number, since it is larger than the sum of its proper divisors (1).
124102030471 is an equidigital number, since it uses as much as digits as its factorization.
124102030471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 124102030471 its reverse (174030201421), we get a palindrome (298132231892).
The spelling of 124102030471 in words is "one hundred twenty-four billion, one hundred two million, thirty thousand, four hundred seventy-one".
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