Base | Representation |
---|---|
bin | 10010000011110011010… |
… | …010001011011011011101 |
3 | 11101122022200001100121011 |
4 | 102003303102023123131 |
5 | 130313113221211031 |
6 | 2350042231135221 |
7 | 155442635506603 |
oct | 22036322133335 |
9 | 4348280040534 |
10 | 1241032210141 |
11 | 439356368969 |
12 | 18062b214511 |
13 | 9004b4743a9 |
14 | 440cdc29873 |
15 | 224371176b1 |
hex | 120f348b6dd |
1241032210141 has 2 divisors, whose sum is σ = 1241032210142. Its totient is φ = 1241032210140.
The previous prime is 1241032210129. The next prime is 1241032210151. The reversal of 1241032210141 is 1410122301421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1130881238041 + 110150972100 = 1063429^2 + 331890^2 .
It is an emirp because it is prime and its reverse (1410122301421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1241032210141 - 217 = 1241032079069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1241032210151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620516105070 + 620516105071.
It is an arithmetic number, because the mean of its divisors is an integer number (620516105071).
Almost surely, 21241032210141 is an apocalyptic number.
It is an amenable number.
1241032210141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241032210141 is an equidigital number, since it uses as much as digits as its factorization.
1241032210141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 1241032210141 its reverse (1410122301421), we get a palindrome (2651154511562).
The spelling of 1241032210141 in words is "one trillion, two hundred forty-one billion, thirty-two million, two hundred ten thousand, one hundred forty-one".
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