Base | Representation |
---|---|
bin | 100100111111010… |
… | …1000001001010101 |
3 | 10012111110011101121 |
4 | 1021332220021111 |
5 | 10020213413013 |
6 | 323054123541 |
7 | 42520431112 |
oct | 11176501125 |
9 | 3174404347 |
10 | 1241154133 |
11 | 58766551a |
12 | 2a77b05b1 |
13 | 16a1a343b |
14 | baba3909 |
15 | 73e6958d |
hex | 49fa8255 |
1241154133 has 2 divisors, whose sum is σ = 1241154134. Its totient is φ = 1241154132.
The previous prime is 1241154113. The next prime is 1241154169. The reversal of 1241154133 is 3314511421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1025152324 + 216001809 = 32018^2 + 14697^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1241154133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1241154098 and 1241154107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1241154113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620577066 + 620577067.
It is an arithmetic number, because the mean of its divisors is an integer number (620577067).
Almost surely, 21241154133 is an apocalyptic number.
It is an amenable number.
1241154133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241154133 is an equidigital number, since it uses as much as digits as its factorization.
1241154133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 25.
The square root of 1241154133 is about 35230.0174992860. The cubic root of 1241154133 is about 1074.6702815742.
Adding to 1241154133 its reverse (3314511421), we get a palindrome (4555665554).
The spelling of 1241154133 in words is "one billion, two hundred forty-one million, one hundred fifty-four thousand, one hundred thirty-three".
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