Base | Representation |
---|---|
bin | 1011010010011110011101… |
… | …0000101111010111000101 |
3 | 1121221120122102212100221221 |
4 | 2310213213100233113011 |
5 | 3111324324323141313 |
6 | 42222002422440341 |
7 | 2420511635002606 |
oct | 264474720572705 |
9 | 47846572770857 |
10 | 12412040443333 |
11 | 3a55a0a281513 |
12 | 14856532930b1 |
13 | 6c05b1682cbb |
14 | 30ca62cc9dad |
15 | 167ceb8c7c8d |
hex | b49e742f5c5 |
12412040443333 has 4 divisors (see below), whose sum is σ = 12412209335328. Its totient is φ = 12411871551340.
The previous prime is 12412040443279. The next prime is 12412040443339. The reversal of 12412040443333 is 33334404021421.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12412040443333 - 229 = 12411503572421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12412040443339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84335713 + ... + 84482758.
It is an arithmetic number, because the mean of its divisors is an integer number (3103052333832).
Almost surely, 212412040443333 is an apocalyptic number.
It is an amenable number.
12412040443333 is a deficient number, since it is larger than the sum of its proper divisors (168891995).
12412040443333 is an equidigital number, since it uses as much as digits as its factorization.
12412040443333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 168891994.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 12412040443333 its reverse (33334404021421), we get a palindrome (45746444464754).
The spelling of 12412040443333 in words is "twelve trillion, four hundred twelve billion, forty million, four hundred forty-three thousand, three hundred thirty-three".
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