Search a number
-
+
12412144113 = 34137381371
BaseRepresentation
bin10111000111101001…
…00100100111110001
31012001000122020210020
423203310210213301
5200410002102423
65411351154053
7616404325035
oct134364444761
935030566706
1012412144113
11529a371646
1224a4975929
13122a668895
1485a6641c5
154c9a324e3
hex2e3d249f1

12412144113 has 4 divisors (see below), whose sum is σ = 16549525488. Its totient is φ = 8274762740.

The previous prime is 12412144111. The next prime is 12412144127. The reversal of 12412144113 is 31144121421.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12412144113 - 21 = 12412144111 is a prime.

It is a super-2 number, since 2×124121441132 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12412144111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2068690683 + ... + 2068690688.

It is an arithmetic number, because the mean of its divisors is an integer number (4137381372).

Almost surely, 212412144113 is an apocalyptic number.

It is an amenable number.

12412144113 is a deficient number, since it is larger than the sum of its proper divisors (4137381375).

12412144113 is an equidigital number, since it uses as much as digits as its factorization.

12412144113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4137381374.

The product of its digits is 768, while the sum is 24.

Adding to 12412144113 its reverse (31144121421), we get a palindrome (43556265534).

The spelling of 12412144113 in words is "twelve billion, four hundred twelve million, one hundred forty-four thousand, one hundred thirteen".

Divisors: 1 3 4137381371 12412144113